TS EAMCET · Maths · Properties of Triangles
Let \(A B C\) be an isosceles triangle with \(B C\) as its base. Then, \(r_1=\)
- A \(a^2\)
- B \(\frac{a^2}{2}\)
- C \(R^2 \sin ^2 A\)
- D \(R^2 \sin ^2 2 B\)
Answer & Solution
Correct Answer
(C) \(R^2 \sin ^2 A\)
Step-by-step Solution
Detailed explanation
We have, \(A B C\) be an isosceles triangle, \(B C\) as its base. \( \therefore \quad \angle B=\angle C \) We know that, \( r=4 R \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2} \)…
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