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TS EAMCET · Maths · Differentiation

If \(y=\frac{1}{x}+\cos 2 x\), then \(\frac{d^2 y}{d x^2}\) is equal to

  1. A \(\frac{2}{x^3}+4 y-\frac{4}{x}\)
  2. B \(4 y-\frac{4}{x}-\frac{2}{x^3}\)
  3. C \(\frac{2}{x^3}+\frac{4}{x}-4 y\)
  4. D \(4 y-\frac{4}{x}-\frac{1}{x^3}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{2}{x^3}+\frac{4}{x}-4 y\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & y=\frac{1}{x}+\cos 2 x \\ & \Rightarrow \quad \frac{d y}{d x}=\frac{-1}{x^2}-2 \sin 2 x \Rightarrow \frac{d^2 y}{d x^2}=\frac{2}{x^3}-4 \cos 2 x \\ & =\frac{2}{x^3}-4\left(y-\frac{1}{x}\right)=\frac{2}{x^3}+\frac{4}{x}-4 y \\ & \end{aligned}\)
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