TS EAMCET · Maths · Vector Algebra
Let \(\bar{a}\) and \(\bar{b}\) be two vectors such that \(|\bar{a}|=|\bar{b}|\) and \(|\bar{a}+2 \bar{b}|=|2 \bar{a}-\bar{b}|\). If \(\bar{c}\) is a vector parallel to \(\bar{a}\) then the angle between \(\bar{b}\) and \(\bar{c}\) is
- A \(0^{\circ}\)
- B \(30^{\circ}\)
- C \(60^{\circ}\)
- D \(90^{\circ}\)
Answer & Solution
Correct Answer
(D) \(90^{\circ}\)
Step-by-step Solution
Detailed explanation
\(|\\bar{a}+2 \\bar{b}|^2 = |2 \\bar{a}-\\bar{b}|^2\) \(( \\bar{a}+2 \\bar{b} ) \\cdot ( \\bar{a}+2 \\bar{b} ) = ( 2 \\bar{a}-\\bar{b} ) \\cdot ( 2 \\bar{a}-\\bar{b} ) \)…
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