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TS EAMCET · Maths · Vector Algebra

Let \(\bar{a}\) and \(\bar{b}\) be two vectors such that \(|\bar{a}|=|\bar{b}|\) and \(|\bar{a}+2 \bar{b}|=|2 \bar{a}-\bar{b}|\). If \(\bar{c}\) is a vector parallel to \(\bar{a}\) then the angle between \(\bar{b}\) and \(\bar{c}\) is

  1. A \(0^{\circ}\)
  2. B \(30^{\circ}\)
  3. C \(60^{\circ}\)
  4. D \(90^{\circ}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(90^{\circ}\)

Step-by-step Solution

Detailed explanation

\(|\\bar{a}+2 \\bar{b}|^2 = |2 \\bar{a}-\\bar{b}|^2\) \(( \\bar{a}+2 \\bar{b} ) \\cdot ( \\bar{a}+2 \\bar{b} ) = ( 2 \\bar{a}-\\bar{b} ) \\cdot ( 2 \\bar{a}-\\bar{b} ) \)…
From TS EAMCET
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