TS EAMCET · Maths · Definite Integration
\(\int_{-\pi / 2}^{\pi / 2} \sin |x| d x\) is equal to
- A \(0\)
- B \(1\)
- C \(2\)
- D \(\pi\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
Let \[ \begin{aligned} I & =\int_{-\pi / 2}^{\pi / 2} \sin |x| d x \\ & =2 \int_0^{\pi / 2} \sin x d x \\ & =2[-\cos x]_0^{\pi / 2} \\ & =2 \end{aligned} \]
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