TS EAMCET · Maths · Probability
If three smallest squares are chosen at random on a chess board then the probability of getting them in such a way that they are all together in a row or in a column is
- A \(\frac{73}{5208}\)
- B \(\frac{1}{434}\)
- C \(\frac{96}{217}\)
- D \(\frac{479}{504}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{434}\)
Step-by-step Solution
Detailed explanation
Total ways to choose 3 squares: \( \binom{64}{3} = \frac{64 \times 63 \times 62}{3 \times 2 \times 1} = 41664 \). Ways to choose 3 adjacent squares in a row: \( 8 \text{ rows} \times 6 \text{ positions/row} = 48 \). Ways to choose 3 adjacent squares in a column:…
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