TS EAMCET · Maths · Straight Lines
In an isosceles triangle the ends of its base are \((2 a, 0)\), \((0, a)\) and one of its two other sides is a horizontal line other \(\mathrm{X}\)-axis. If the third vertex is \(\left(x_1, y_1\right)\) then \(x_1+y_1=\)
- A \(\frac{9 a}{2}\)
- B \(3 a\)
- C \(\frac{9 a}{4}\)
- D \(5 a\)
Answer & Solution
Correct Answer
(C) \(\frac{9 a}{4}\)
Step-by-step Solution
Detailed explanation
Since AC parallel to \(\mathrm{x}\) - axis \[ \therefore \mathrm{y}_1=\mathrm{a} \] Now \(\mathrm{AC}=\mathrm{BC} \Rightarrow \mathrm{AC}^2=\mathrm{BC}^2\)…
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