TS EAMCET · Maths · Trigonometric Ratios & Identities
In a triangle \(A B C\). If \(\cos A \cos B+\sin A \sin B \sin C=1\), then \(\sin A+\sin B+\sin C=\)
- A \(\frac{2+\sqrt{3}}{2}\)
- B \(1+\sqrt{2}\)
- C \(\frac{2 \sqrt{3}-1}{2}\)
- D \(\frac{3+\sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(B) \(1+\sqrt{2}\)
Step-by-step Solution
Detailed explanation
We have, In \(\triangle A B C\), \[ \cos A \cos B+\sin A \sin B \sin C=1 \] \[ \cos A \cos B+\sin A \sin B \sin C=1 \] is possible of \(A=45^{\circ}, B=45^{\circ}, C=90^{\circ}\)…
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