TS EAMCET · Maths · Binomial Theorem
If \((1+x)^n=C_0+C_1 x+C_2 x^2+\ldots+C_n x^n\) for \(n \in N\), then \(C_0+\frac{C_1}{2}+\frac{C_2}{3}+\ldots+\frac{C_n}{n+1}=\)
- A \(\frac{2^n-1}{n+1}\)
- B \(\frac{2^n-1}{n}\)
- C \(\frac{2^{n+1}-1}{n+1}\)
- D \(\frac{2^{n+1}-1}{n}\)
Answer & Solution
Correct Answer
(B) \(\frac{2^n-1}{n}\)
Step-by-step Solution
Detailed explanation
\[ (1+x)^n=C_0+C_1 x+C_2 x^2+\ldots . .+C_n x^n \] Integrate both sides wrt \(x\)…
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