TS EAMCET · Maths · Vector Algebra
Let \(A B C\) be a triangle with \(A(\alpha, 5, \beta)\), \(B(-2,1,6)\) and \(C(1,0,-3)\) as its vertices. If the median through \(B\) is equally inclined to the coordinate axes, then \(\alpha+\beta=\)
- A 10
- B 12
- C 14
- D 16
Answer & Solution
Correct Answer
(D) 16
Step-by-step Solution
Detailed explanation
We have, \(A B C\) be a triangle with vertices \(\begin{aligned} & A(\alpha, 5, \beta), B(-2,1,6) \text { and } C(1,0,-3) \\ & D=\text { Mid-point of } A C \\ & \therefore D\left(\frac{\alpha+1}{2}, \frac{5}{2}, \frac{\beta-3}{2}\right) \end{aligned}\)…
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