TS EAMCET · Maths · Properties of Triangles
In a \(\triangle A B C\), if the medians \(A D\) and \(B E\) are such that \(A D=4, \angle D A B=\frac{\pi}{6}\) and \(\angle A B E=\frac{\pi}{3}\) then the area of \(\triangle A B C\) (in square units) is
- A \(\frac{16}{3 \sqrt{3}}\)
- B \(\frac{48}{3 \sqrt{3}}\)
- C \(\frac{64}{3 \sqrt{3}}\)
- D \(\frac{32}{3 \sqrt{3}}\)
Answer & Solution
Correct Answer
(D) \(\frac{32}{3 \sqrt{3}}\)
Step-by-step Solution
Detailed explanation
In \(\triangle A B C\), \(A D\) and \(B E\) are median of \(\triangle A B C\) \( A D=4, \angle D A B=\frac{\pi}{6} \text { and } \angle A B E=\frac{\pi}{3} \)…
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