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TS EAMCET · Maths · Differentiation

If \(\frac{d}{d x}\left[(x+1)\left(x^2+1\right)\left(x^4+1\right)\left(x^8+1\right)\right]\) \(=\left(15 x^p-16 x^q+1\right)(x-1)^{-2}\), then \((p, q)\) is equal to

  1. A \((12,11)\)
  2. B \((15,14)\)
  3. C \((16,14)\)
  4. D \((16,15)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \((16,15)\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \frac{d}{d x}\left[(x+1)\left(x^2+1\right)\left(x^4+1\right)\left(x^8+1\right)\right] \\ &=\frac{\left(15 x^\rho-16 x^9+1\right)}{(x-1)^2} \\ & \text { LHS }= \frac{d}{d…