TS EAMCET · Maths · Limits
If , then
- A
- B
- C
- D
Answer & Solution
Correct Answer
(D)
Step-by-step Solution
Detailed explanation
limx→23x2-ax+5bx-2=17 Since, limit exists, numerator must be zero at x=2 ⇒12-2a+5b=0 ⇒5b+12=2a Using L'Hospital's rule, we get limx→26x-a1=17 ⇒6x=17+a ⇒a=-5 So, 5b+12=2-5 ⇒b=-225 So, ab=-5-225 Hence, ab=22
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