TS EAMCET · Maths · Differentiation
If \(x y \neq 0, x+y \neq 0\) and \(x^m y^n=(x+y)^{m+n}\), where \(m, n \notin N\), then \(\frac{d y}{d x}\) is equal to
- A \(\frac{y}{x}\)
- B \(\frac{x+y}{x y}\)
- C \(x y\)
- D \(\frac{x}{y}\)
Answer & Solution
Correct Answer
(A) \(\frac{y}{x}\)
Step-by-step Solution
Detailed explanation
Given, \(x^m y^n=(x+y)^{m+n}\) On taking log on both sides, we get \(m \log x+n \log y=(m+n) \log (x+y)\) On differentiating w.r.t. \(x\), we get…
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