TS EAMCET · Chemistry · Structure of Atom
The degeneracy of the level of hydrogen atoms that contain the energy of \(\left(\frac{-R_{\mathrm{H}}}{16}\right)\) is
- A 4
- B 16
- C 9
- D 12
Answer & Solution
Correct Answer
(B) 16
Step-by-step Solution
Detailed explanation
Given, \(E=\frac{-R_{\mathrm{H}}}{16}\) We know that, \(E=\frac{-R_{\mathrm{H}}}{n^2}=\frac{-R_{\mathrm{H}}}{16}, \therefore n=4\) Thus, degeneracy for \(n=4\) will be, Hence, total degeneracy of orbital for \(n=4\) will be 16 .
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