TS EAMCET · Maths · Three Dimensional Geometry
If \((2,3,-3)\) is one end of a diameter of the sphere \(x^2+y^2+z^2-6 x-12 y-2 z+20=0\), then the other end of the diameter is
- A \((4,9,-1)\)
- B \((4,9,5)\)
- C \((-8,-15,1)\)
- D \((8,15,5)\)
Answer & Solution
Correct Answer
(B) \((4,9,5)\)
Step-by-step Solution
Detailed explanation
The equation of the sphere is \(x^2+y^2+z^2-6 x-12 y-2 z+20=0\) So, the centre of the sphere is \((-u,-v,-w)=(3,6,1)\) given the one end of the diameter is \((2,3,-3)\), let the other end of the diameter is \((\alpha, \beta, \gamma)\). Since, \(O\) is the mid point of the…
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