TS EAMCET · Maths · Basic of Mathematics
If \(a, b\) and \(n\) are natural numbers, then \(a^{2 n-1}+b^{2 n-1}\) is divisible by
- A \(a+b\)
- B \(a-b\)
- C \(a^3+b^3\)
- D \(a^2+b^2\)
Answer & Solution
Correct Answer
(A) \(a+b\)
Step-by-step Solution
Detailed explanation
Here, we see that \((2 n-1)\) is an odd number \(\therefore a^{2 n-1}+b^{2 n-1}\) is divisible by \(a+b\).
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