TS EAMCET · Maths · Functions
If \([x]\) represent greatest integer \(\leq x\) and \([\alpha, \beta]\) is the set of all real values of \(x\) for which the real function \(f(x)=\frac{\sqrt{3+x}+\sqrt{3-x}}{\sqrt{[x]+2}}\) is defined, then \(f^2(\alpha+1)+5 f^2(\beta)=\)
- A \(0\)
- B \(\frac{36}{5}\)
- C \(12\)
- D \(1\)
Answer & Solution
Correct Answer
(C) \(12\)
Step-by-step Solution
Detailed explanation
The given function \(f(x)=\frac{\sqrt{3+x}+\sqrt{3-x}}{\sqrt{[x]+2}}\), then function \(f\) is defined if \(3+x \geq 0,3-x \geq 0\) and \([x]+2>0\)…
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