TS EAMCET · Maths · Quadratic Equation
If \(x\) is real, then the interval in which no value of the expression \(\frac{2\left(x^2+2 x-11\right)}{2 x-5}\) lies, is
- A \((2,5)\)
- B \((3,6)\)
- C \((3,4)\)
- D \((6,8)\)
Answer & Solution
Correct Answer
(D) \((6,8)\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { Let } y=\frac{2\left(x^2+2 x-1\right)}{2 x-5} \\ & \Rightarrow 2 x y-5 y=2 x^2+4 x-22 \\ & \Rightarrow 2 x^2+2 x(2-y)-22+5 y=0 \\ & x \in R \end{aligned} \]…
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