TS EAMCET · Maths · Determinants
\(1 \mathrm{f}\left|\begin{array}{ccc}x^2+3 x & x+1 & x-3 \\ x-1 & 2-x & x+4 \\ x-3 & x-3 & 3 x\end{array}\right|=a_0\) \(+a_3 x^3+a_4 x^4\), then \(\left(a_1+a_3\right)+2\left(a_0+a_2+a_4\right)=\)
- A -1
- B 0
- C 1
- D -29
Answer & Solution
Correct Answer
(A) -1
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} & \left|\begin{array}{ccc} x^2+3 x & x+1 & x-3 \\ x-1 & 2-x & x+4 \\ x-3 & x-3 & 3 x \end{array}\right| \\ = & a_0+a_1 x+a_2 x^2+a_3 x^3+a_4 x^4 \end{aligned} \] Put \(x=1\) both sides, we get…
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