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TS EAMCET · Maths · Quadratic Equation

If \(x=\sqrt{\frac{2+\sqrt{3}}{2-\sqrt{3}}}\), then \(x^2(x-4)^2\) is equal to :

  1. A 7
  2. B 4
  3. C 2
  4. D 1
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Answer & Solution

Correct Answer

(D) 1

Step-by-step Solution

Detailed explanation

\(\because \quad x=\sqrt{\frac{2+\sqrt{3}}{2-\sqrt{3}}}=\sqrt{\frac{(2+\sqrt{3})(2+\sqrt{3})}{(2-\sqrt{3})(2+\sqrt{3})}}\) \(=\frac{2+\sqrt{3}}{\sqrt{4-3}}=2+\sqrt{3}\) \(\therefore x^2(x-4)^2=(2+\sqrt{3})^2(2+\sqrt{3}-4)^2\) \(=(\sqrt{3}+2)^2(\sqrt{3}-2)^2\)…
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