TS EAMCET · Chemistry · Chemical Kinetics
For a first order reaction, the graph between \(\log \frac{a}{(a-x)}\) (on \(y\)-axis) and time (in min, on \(x\)-axis) gave a straight line passing through origin. The slope is \(2 \times 10^{-3} \mathrm{~min}^{-1}\). What is the rate constant (in \(\min ^{-1}\) )?
- A \(2 \times 10^{-3}\)
- B \(\frac{2 \times 10^{-3}}{2.303}\)
- C \(4.606 \times 10^{-3}\)
- D \(0.5 \times 10^{-5}\)
Answer & Solution
Correct Answer
(C) \(4.606 \times 10^{-3}\)
Step-by-step Solution
Detailed explanation
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