TS EAMCET · Maths · Circle
The point where the line \(4 x-3 y+7=0\) touches the circle \(x^2+y^2-6 x+4 y-12=0\) is
- A \((1,1)\)
- B \((1,-1)\)
- C \((-1,1)\)
- D \((-1,-1)\)
Answer & Solution
Correct Answer
(C) \((-1,1)\)
Step-by-step Solution
Detailed explanation
Let \((a, b)\) be the point where line \(4 x-3 y+7=0\) touches the circle \(x^2+y^2-6 x+4 y-12=0\). Now, equation of the tangent at \((a, b)\) to the given circle is…
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