TS EAMCET · Maths · Functions
If \(\frac{x^2}{(2 x-1)(x+2)(x-3)}\) \(=A+\frac{B}{2 x-1}+\frac{C}{x+2}+\frac{D}{x-3}\), then \(A\) is equal to
- A \(\frac{1}{2}\)
- B \(-\frac{1}{50}\)
- C \(-\frac{8}{25}\)
- D \(\frac{27}{25}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
Given that \(\begin{gathered} \frac{x^3}{(2 x-1)(x+2)(x-3)}= \\ A+\frac{B}{2 x-1}+\frac{C}{x+2}+\frac{D}{x-3} \end{gathered}\) Let…
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