TS EAMCET · Maths · Differentiation
If \(y=\left(1-x^2\right) \operatorname{Tanh}^{-1} x\) then \(\frac{d^2 y}{d x^2}=\)
- A \(\frac{2 x y}{\left(1+x^2\right)^2}\)
- B \(-\frac{(x+y)}{\left(1-x^2\right)^2}\)
- C \(\frac{2(x y)}{1-x^2}\)
- D \(-\frac{2(x+y)}{1-x^2}\)
Answer & Solution
Correct Answer
(D) \(-\frac{2(x+y)}{1-x^2}\)
Step-by-step Solution
Detailed explanation
\(\frac{dy}{dx} = -2x \operatorname{Tanh}^{-1} x + (1-x^2) \frac{1}{1-x^2}\) \(\frac{dy}{dx} = -2x \operatorname{Tanh}^{-1} x + 1\) \(\frac{d^2 y}{dx^2} = -2 \left( (1) \operatorname{Tanh}^{-1} x + x \frac{1}{1-x^2} \right) + 0\)…
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