TS EAMCET · Maths · Matrices
\(A=\left[\begin{array}{lll}1 & 0 & 1 \\ 0 & 1 & 1 \\ 0 & 1 & 0\end{array}\right] \Rightarrow A^2-2 A=\)
- A \(A^{-1}\)
- B \(-A^{-1}\)
- C \(I\)
- D \(-I\)
Answer & Solution
Correct Answer
(B) \(-A^{-1}\)
Step-by-step Solution
Detailed explanation
Given, \(A=\left[\begin{array}{lll}1 & 0 & 1 \\ 0 & 1 & 1 \\ 0 & 1 & 0\end{array}\right]\) \(\therefore A^2-2 A=\left[\begin{array}{lll} 1 & 1 & 1 \\ 0 & 2 & 1 \\ 0 & 1 & 1 \end{array}\right]-\left[\begin{array}{lll} 2 & 0 & 2 \\ 0 & 2 & 2 \\ 0 & 2 & 0 \end{array}\right]\)…
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