TS EAMCET · Maths · Quadratic Equation
If \(x^2+2 p x-2 p+8>0\) for all real values of \(x\), then the set of all possible values of \(p\) is
- A \((2,4)\)
- B \((-\infty,-4)\)
- C \((2, \infty)\)
- D \((-4,2)\)
Answer & Solution
Correct Answer
(D) \((-4,2)\)
Step-by-step Solution
Detailed explanation
Given, \(x^2+2 p x-2 p+8>0\), for all real values of \(x\).…
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