TS EAMCET · Maths · Probability
An unbiased coin is tossed to get 2 points for turning up a head and one point for the tail. If three unbiased coins are tossed simultaneously, then the probability of getting a total of odd number of points is
- A \(\frac{1}{2}\)
- B \(\frac{1}{4}\)
- C \(\frac{1}{8}\)
- D \(\frac{3}{8}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
We are getting a odd number of point, if it will comes (two head, one tail and three tail) \[ \because \quad P(H)=P(T)=\frac{1}{2} \] \(\therefore\) Required probability \(=\) Probability of getting two heads and one tail + Probability of all three tails…
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