TS EAMCET · Maths · Continuity and Differentiability
Assertion (A) \(f(x)=|x-a|+|x-b|\), is continuous on \(\mathbf{R}\)Reason (R) \(\frac{|x-\alpha|}{x-\alpha}\) is continuous at \(x \in \mathbf{R}-\{\alpha\}\). The correct option among the following is
- A (A) is true, (R) is true and (R) is the correct explanation for \(\mathrm{A}\)
- B \((\mathrm{A})\) is true, \((\mathrm{R})\) is true but \((\mathrm{R})\) is not the correct explanation for \(A\)
- C \((A)\) is true but \((R)\) is false
- D (A) is false but \((R)\) is true
Answer & Solution
Correct Answer
(B) \((\mathrm{A})\) is true, \((\mathrm{R})\) is true but \((\mathrm{R})\) is not the correct explanation for \(A\)
Step-by-step Solution
Detailed explanation
The function \(f(x)=|x-a|+|x-b|\) is continuous on \(R\). The function \(\frac{|x-\alpha|}{x-\alpha}\) is continuous at \(x \in \mathbf{R}-\{\alpha\}\)
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