TS EAMCET · Maths · Straight Lines
If two equal sides of an isosceles triangle are given by the equations \(7 x-y+3=0\) and \(x+y-3=0\), then the equation of its third side passing through the point \((2,-5)\) is
- A \(x-3 y=17\)
- B \(3 x-y=11\)
- C \(7 x+2 y=4\)
- D none of these
Answer & Solution
Correct Answer
(A) \(x-3 y=17\)
Step-by-step Solution
Detailed explanation
The third side of the isosceles triangle is parallel to the angle bisector of the given lines \(7 x-y+3=0\) and \(x+y-3=0\). Now, the equation of angle bisectors are \(\frac{7 x-y+3}{\sqrt{50}}= \pm \frac{x+y-3}{\sqrt{2}}\) \(\Rightarrow \quad 7 x-y+3= \pm 5(x+y-3)\) or…
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