TS EAMCET · Maths · Three Dimensional Geometry
Let \(\pi_1\) be a plane passing through the point \(\bar{i}+\bar{j}+\bar{k}\) and perpendicular to the vector \(-\bar{j}+2 \bar{k}\). Let the line \(\mathrm{L}\) passing through the points \(3 \bar{i}-2 \bar{j}+\bar{k}\) and \(-\bar{i}+3 \bar{j}+\bar{k}\) be a normal to the plane \(\pi_2\). If the angle between the planes \(\pi_1\) and \(\pi_2\) is \(\theta\) then \(\cos \theta=\)
- A \(\sqrt{\frac{5}{41}}\)
- B \(\frac{-14}{\sqrt{205}}\)
- C \(\frac{\pi}{4}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{\frac{5}{41}}\)
Step-by-step Solution
Detailed explanation
We have to find angle between two plans \(\pi_1\) and \(\pi_2\). for plane \(\pi_1, \pi_2=\pi_1, \bar{\pi}_1=-\hat{\mathrm{j}}+\mathrm{z} \hat{\mathrm{k}}\) and for plane \(\pi_2, \bar{\pi}_2=4 \hat{\mathrm{i}}-5 \hat{\mathrm{j}}\) hence…
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