TS EAMCET · Maths · Vector Algebra
If the vector \(\mathbf{a}=2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}}\) and \(\mathbf{b}\) are collinear and \(|\mathbf{b}|=21\), then \(\mathbf{b}\) equal to:
- A \(\pm(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}})\)
- B \(\pm 3(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}})\)
- C \((\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}})\)
- D \(\pm 21(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}})\)
Answer & Solution
Correct Answer
(B) \(\pm 3(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}})\)
Step-by-step Solution
Detailed explanation
Given that \(\mathbf{a}=2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}}\) and \(|\mathbf{b}|=21\) Now, taking option (b) Let…
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