TS EAMCET · Maths · Straight Lines
Let \(A=(2,3), B=(3,-5)\) be two vertices of \(\triangle A B C\) such that \(C\) is a point on the line \(L \equiv 3 x+4 y-5=0\). Then the locus of the centroid of \(\triangle A B C\) is a line parallel to
- A \(L=0\)
- B AB
- C AC
- D BC
Answer & Solution
Correct Answer
(A) \(L=0\)
Step-by-step Solution
Detailed explanation
Given, \(A=(2,3), B(3,-5), C=(x, y)\) Let centroid of \(\triangle A B C\) is \((h, k)\) \(\begin{array}{ll} \therefore & h=\frac{2+3+x}{3}, k=\frac{3-5+y}{3} \\ \Rightarrow & x=3 h-5 \Rightarrow y=3 k+2 \end{array}\) \(C\) lie on line \(3 x+4 y-5=0\)…
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