The change in enthalpy ΔH in kJmol-1 for the reaction is Mg+2 F→MgF2 Given: EA of F=328 kJ mol-1,IE1 of Mg=737 kJ mol-1,IE2 of Mg=1451 kJ mol-1

TS EAMCET · Chemistry · Thermodynamics (C)

The change in enthalpy $[Δ H]$ in ${kJmol}^{- 1}$ for the reaction is $Mg + 2 F \to {MgF}_{2}$ Given: $EA$ of $F = 328 kJ {mol}^{- 1}, {IE}_{1}$ of $Mg = 737 kJ {mol}^{- 1}, {IE}_{2}$ of $Mg = 1451 kJ {mol}^{- 1}$

A $3064$
B $876$
C $1860$
D $1532$

Verified Solution

Answer & Solution

Correct Answer

(D) $1532$

Step-by-step Solution

Detailed explanation

The enthalpy change accompanying a reaction is called the reaction enthalpy. Enthalpy of a reaction depends on the conditions under which a reaction is carried out. The change in enthalpy of the reactionMg+2 F→MgF2 is calculated as given below…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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