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TS EAMCET · Maths · Differentiation

If \(f(x)=\frac{1}{1+\frac{1}{x}}\) and \(g(x)=\frac{1}{1+\frac{1}{f(x)}}\), then \(g^{\prime}(2)\) is equal to

  1. A \(\frac{1}{5}\)
  2. B \(\frac{1}{25}\)
  3. C \(5\)
  4. D \(\frac{1}{16}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{25}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \quad f(x)=\frac{1}{1+\frac{1}{x}}=\frac{x}{1+x} \\ & \text { and } \quad g(x)=\frac{1}{1+\frac{1}{f(x)}}=\frac{1}{1+\frac{1+x}{x}}=\frac{x}{2 x+1} \\ & \therefore \quad g^{\prime}(x)=\frac{(2 x+1) \cdot 1-x(2)}{(2 x+1)^2}=\frac{1}{(2 x+1)^2} \\ & \text { Now,…