TS EAMCET · Maths · Quadratic Equation
If \(\alpha, \beta, \gamma\) are the roots of the equation \(5 x^3-3 x^2+2 x-4\) \(=0\) then \(\sum \alpha^2 \beta^2=\).
- A \(\frac{4}{5}\)
- B \(\frac{-2}{5}\)
- C \(\frac{2}{5}\)
- D \(\frac{-4}{5}\)
Answer & Solution
Correct Answer
(D) \(\frac{-4}{5}\)
Step-by-step Solution
Detailed explanation
We have an equation \(5 x^3-3 x^2+2 x-4=0\) with roots \(\alpha, \beta\) and \(\gamma\) Now \(\alpha+\beta+\gamma=\frac{3}{5}\) \(\alpha \beta+\beta \gamma+\gamma \alpha=\frac{2}{5}\) and \(\alpha \beta \gamma=\frac{4}{5}\) Now…
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