TS EAMCET · Maths · Application of Derivatives
If the slope of the tangent drawn at any point \((x, y)\) on the curve \(y=f(x)\) is \(\left(6 x^2+10 x-9\right)\) and \(f(2)=0\), then \(f(-2)=\)
- A 0
- B 4
- C -6
- D -13
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x}=6 x^2+10 x-9\) \(\begin{aligned} & f(x)=y=2 x^3+5 x^2-9 x+C \\ & \Rightarrow f(2)=16+20-18+C=0 \Rightarrow C=-18 \\ & f(x)=2 x^3+5 x^2-9 x-18 \\ & f(-2)=-16+20+18-18=4\end{aligned}\)
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