ExamBro
ExamBro
TS EAMCET · Maths · Application of Derivatives

If the slope of the tangent drawn at any point \((x, y)\) on the curve \(y=f(x)\) is \(\left(6 x^2+10 x-9\right)\) and \(f(2)=0\), then \(f(-2)=\)

  1. A 0
  2. B 4
  3. C -6
  4. D -13
Verified Solution

Answer & Solution

Correct Answer

(B) 4

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}=6 x^2+10 x-9\) \(\begin{aligned} & f(x)=y=2 x^3+5 x^2-9 x+C \\ & \Rightarrow f(2)=16+20-18+C=0 \Rightarrow C=-18 \\ & f(x)=2 x^3+5 x^2-9 x-18 \\ & f(-2)=-16+20+18-18=4\end{aligned}\)