TS EAMCET · Maths · Functions
The domain of the real valued function \(f(x)=\sqrt{\cos (\sin x)}+\cos ^{-1}\left(\frac{1+x^2}{2 x}\right)\) is
- A \((-1,1)\)
- B \([-1,1]\)
- C \(R-(-1,1)\)
- D \(\{-1,1\}\)
Answer & Solution
Correct Answer
(D) \(\{-1,1\}\)
Step-by-step Solution
Detailed explanation
\(\left|\frac{1+x^2}{2 x}\right| \geq 1 \Rightarrow\left|\frac{1+x^2}{2 x}\right|=1\) for \(x=1\) or \(x=-1\) Thus \(\cos \left(\frac{1+x^2}{2 x}\right)\) is deîned for \(x= \pm 1\)…
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