TS EAMCET · Maths · Ellipse
If the line \(\mathrm{x} \cos \alpha+\mathrm{y} \sin x=2 \sqrt{3}\) is a tangent to the ellipse \(\frac{x^2}{16}+\frac{y^2}{8}=1\) and \(\alpha\) is an acute angle then \(\alpha=\)
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{4}\)
Step-by-step Solution
Detailed explanation
\(x \cos \alpha+y \sin \alpha=2 \sqrt{3}\) \[ \frac{x^2}{16}+\frac{y^2}{8}=1 \] We know that if \(x \cos \alpha+y \sin \alpha=\mathrm{p}\) is tangent to ellipse \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\) then \[ p^2=a^2 \cos ^2 \alpha+b^2 \sin ^2 \alpha \]…
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