TS EAMCET · Maths · Hyperbola
If the latus rectum of a hyperbola subtends an angle of \(120^{\circ}\) at its centre, then its eccentricity is
- A \(\frac{\sqrt{3}+2}{\sqrt{2}}\)
- B \(\frac{\sqrt{3}+\sqrt{5}}{2}\)
- C \(\frac{\sqrt{3}-\sqrt{2}}{3}\)
- D \(\frac{\sqrt{3}+\sqrt{7}}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{\sqrt{3}+\sqrt{7}}{2}\)
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