TS EAMCET · Chemistry · Solid State
The angle between (100) and (110) planes of FCC lattice is
- A \(90^{\circ}\)
- B \(0^{\circ}\)
- C \(45^{\circ}\)
- D \(120^{\circ}\)
Answer & Solution
Correct Answer
(C) \(45^{\circ}\)
Step-by-step Solution
Detailed explanation
Angle between (100) and (110) planes of fcc lattice is \(\cos \phi=\frac{h_1 h_2+k_1 k_2+l_1 l_2}{\sqrt{h_1^2+k_1^2+l_1^2 \sqrt{h_2^2+k_2^2+l_2^2}}}\) \(\cos \phi=\frac{(1 \times 1)+(0 \times 1)+(0 \times 0)}{\sqrt{(1)^2+(0)^2+(0)^2} \sqrt{(1)^2+(1)^2+(0)^2}}\)…
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