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TS EAMCET · Chemistry · Alcohols Phenols and Ethers

Optically active

was found to have lost its optical activity after standing in water containing a few drops of acids, mainly due to the formation of

  1. A \(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2\)
  2. B \(\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_3\)
  3. D \(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_3\)

Step-by-step Solution

Detailed explanation

The above optically active compound undergo dehydration with few drops of acid and form stable alkene through the formation of stable carbocation.
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