TS EAMCET · Chemistry · Some Basic Concepts of Chemistry
Combustion of \(10 \mathrm{ml}\) of a gaseous hydrocarbon gives \(40 \mathrm{ml}\) of \(\mathrm{CO}_2\) and \(50 \mathrm{ml}\) of water vapour under the same conditions. The molecular formula of the hydrocarbon is
- A \(\mathrm{C}_4 \mathrm{H}_6\)
- B \(\mathrm{C}_4 \mathrm{H}_8\)
- C \(\mathrm{C}_3 \mathrm{H}_4\)
- D \(\mathrm{C}_4 \mathrm{H}_{10}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{C}_4 \mathrm{H}_{10}\)
Step-by-step Solution
Detailed explanation
Ratio of volume \(=10: 40: 50=1: 4: 5\) In hydrocarbon, all carbon atoms are from \(\mathrm{CO}_2 10 \mathrm{~mL}\) of hydrocarbon produce \(40 \mathrm{~mL}\) of \(\mathrm{CO}_2=1: 4\) \(1 \mathrm{~mol}\) of hydrocarbon has \(4 \mathrm{~mol}\) of \(\mathrm{C}\).…
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