TS EAMCET · Maths · Straight Lines
If the equation of a line parallel to \(3 x-2 y+5=0\) and at a distance of 5 units from it is \(3 x-2 y+C=0\), then \(C\) is equal to
- A \(5\left(\frac{1 \pm \sqrt{13}}{\sqrt{13}}\right)\)
- B \(5( \pm \sqrt{13}+1)\)
- C \(5(\sqrt{13} \pm 1)\)
- D \(5\left(\frac{-1 \pm \sqrt{13}}{\sqrt{13}}\right)\)
Answer & Solution
Correct Answer
(B) \(5( \pm \sqrt{13}+1)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} &\frac{|c-5|}{\sqrt{9+4}}=5 \Rightarrow|c-5|=5 \sqrt{13} \\ & \Rightarrow \quad c-5= \pm 5 \sqrt{13} \\ & \Rightarrow \quad c=5 \pm 5 \sqrt{13}=5(1 \pm \sqrt{13})\end{aligned}\)
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