TS EAMCET · Maths · Differential Equations
The solution of the differential equation \(\frac{d y}{d x}=\frac{x-2 y+1}{2 x-4 y}\) is
- A \((x-2 y)^2+2 x=c\)
- B \((x-2 y)^2+x=c\)
- C \((x-2 y)+2 x^2=c\)
- D \((x-2 y)+x^2=c\)
Answer & Solution
Correct Answer
(A) \((x-2 y)^2+2 x=c\)
Step-by-step Solution
Detailed explanation
Given that, \(\frac{d y}{d x}=\frac{x-2 y+1}{2 x-4 y}\) Put \(x-2 y=z \Rightarrow 1-2 \frac{d y}{d x}=\frac{d z}{d x}\)…
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