TS EAMCET · Maths · Circle
If \(x+k y-4=0\) and \(x+y-5=0\) are conjugate lines with respect to the circle \((x-1)^2+(y-1)^2=3\), then \(k=\)
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
We have, Lines \(x+k y-4=0\) and \(x+y-5=0\) Circle \((x-1)^2+(y-1)^2=3\) \[ \Rightarrow \quad x^2+y^2-2 x-2 y-1=0 \] If the lines \(a_1 x+b_1 y+c_1=0\) and \(a_2 x+b_2 y+c_2=0\) are conjugates lines with respect to the circle \(x^2+y^2+2 g x+2 f y+c=0\), then…
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