TS EAMCET · Maths · Differential Equations
If the differential equation having \(y=\mathrm{Ae}^x+\mathrm{B} \sin x\) as its general solution is
\(f(x) \frac{d^2 y}{d x^2}+g(x) \frac{d y}{d x}+h(x) y=0, \text { then } f(x)+g(x)+h(x)=\)
- A 2 cos x
- B 4 sin x
- C 0
- D cos x - sin x
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x} = \mathrm{Ae}^x+\mathrm{B} \cos x\) \(\frac{d^2 y}{d x^2} = \mathrm{Ae}^x-\mathrm{B} \sin x\) \(y''+y = 2\mathrm{Ae}^x \implies \mathrm{Ae}^x = \frac{y''+y}{2}\) \(y-y'' = 2\mathrm{B} \sin x \implies \mathrm{B} \sin x = \frac{y-y''}{2}\)…
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