TS EAMCET · Maths · Binomial Theorem
The sum to infinite terms of the series \(\frac{3}{10}+\frac{3.7}{10.15}+\frac{3.7 .9}{10.15 .20}+\ldots\) to \(\infty\) is
- A \(\sqrt[4]{125}-1\)
- B \(\frac{5 \sqrt{5}}{3 \sqrt{3}}-\frac{8}{5}\)
- C \(\sqrt[3]{4}-\frac{4}{3}\)
- D \(\sqrt{\frac{5}{3}}-\frac{6}{5}\)
Answer & Solution
Correct Answer
(B) \(\frac{5 \sqrt{5}}{3 \sqrt{3}}-\frac{8}{5}\)
Step-by-step Solution
Detailed explanation
We have series \[ \begin{aligned} & \frac{3}{10}+\frac{3 \cdot 7}{10 \cdot 15}+\frac{3 \cdot 7 \cdot 9}{10 \cdot 15 \cdot 20}+\ldots \\ = & \frac{3}{5 \times 2 !}+\frac{3 \cdot 7}{5^2 \cdot 3 !}+\frac{3 \cdot 7 \cdot 9}{5^3 \cdot 4 !}+\ldots \end{aligned} \] We know that,…
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