TS EAMCET · Maths · Straight Lines
The equations of two altitudes of an equilateral triangle are \(\sqrt{3} x-y+8-4 \sqrt{3}=0\) and \(\sqrt{3} x+y-12-4 \sqrt{3}=0\). The equation of the third altitude is
- A \(\sqrt{3} x+y=4\)
- B \(y=10\)
- C \(x=10\)
- D \(x-\sqrt{3 y}=4\)
Answer & Solution
Correct Answer
(B) \(y=10\)
Step-by-step Solution
Detailed explanation
Equation of altitudes are \[ \begin{aligned} \sqrt{3} x-y+8-4 \sqrt{3} & =0 \\ \sqrt{3} x+y-12-4 \sqrt{3} & =0 \end{aligned} \] and \[ \sqrt{3} x+y-12-4 \sqrt{3}=0 \] Adding Eqs. (i) and (ii),…
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