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TS EAMCET · Maths · Determinants

If \(p\) and \(q\) are two distinct real values of \(\lambda\) for which the system of equations
\(\begin{aligned}
(\lambda-1) x+(3 \lambda+1) y+2 \lambda z & =0 \\
(\lambda-1) x+(4 \lambda-2) y+(\lambda+3) z & =0 \\
2 x+(3 \lambda+1) y+3(\lambda-1) z & =0
\end{aligned}\)
has non-zero solution, then \(p^2+q^2-p q=\)

  1. A 15
  2. B 9
  3. C 3
  4. D 6
Verified Solution

Answer & Solution

Correct Answer

(B) 9

Step-by-step Solution

Detailed explanation

We have, \(\begin{array}{r} (\lambda-1) x+(3 \lambda+1) y+2 \lambda z=0 \\ (\lambda-1) x+(4 \lambda-2) y+(\lambda+3) z=0 \\ 2 x+(3 \lambda+1) y+3(\lambda-1) z=0 \end{array}\) Now, it can be express as \(\quad A X=0\) Where,…
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