TS EAMCET · Maths · Vector Algebra
Let \(a, b, c\) be three vectors such that \(\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{a}}=\overrightarrow{\mathrm{b}} \cdot \overrightarrow{\mathrm{b}}=\overrightarrow{\mathrm{c}} \cdot \overrightarrow{\mathrm{c}}=5\) and \(|\vec{a}+\vec{b}-\vec{c}|^2+|\vec{b}+\vec{c}-\vec{a}|^2+|\vec{c}+\vec{a}-\vec{b}|^2=50\) then \(\vec{a} \vec{b}+\vec{b} \cdot \vec{c}+\vec{c} \cdot \vec{a}=\)
- A \(\frac{5}{2}\)
- B \(-\frac{5}{2}\)
- C 10
- D \(-10\)
Answer & Solution
Correct Answer
(B) \(-\frac{5}{2}\)
Step-by-step Solution
Detailed explanation
\(\vec{a} \cdot \vec{a}=\vec{b} \cdot \vec{b}=\vec{c} \cdot \vec{c}=5\) \(\therefore|\vec{a}|=|\vec{b}|=|\vec{c}|=\sqrt{5}\) also \(|\vec{x}|^2=\vec{x} \cdot \vec{x}\)…
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